This example will determine if an arraylist is sorted not show you how to sort an arraylist . It will check if each element is greater than or equal to the element before it. Each snippet will use guava Ordering utility class calling the Ordering.isOrdered method using a list of numbers/strings in descending and case insensitive are ordered.
Google Guava Numbers sorted @Test
public void is_list_of_numbers_sorted_in_java_with_guava () {
List < Integer > uwConferenceTitles = Lists . newArrayList (
1896 , 1897 , 1901 , 1906 , 1912 ,
1952 , 1959 , 1962 , 1993 , 1998 ,
1999 , 2010 , 2011 , 2012 );
boolean isSorted = Ordering . natural (). isOrdered ( uwConferenceTitles );
assertTrue ( isSorted );
}
Strings sorted @Test
public void is_list_of_strings_sorted_in_java_with_guava () {
List < String > secConferenceEast = Lists . newArrayList (
"Florida" ,
"Georgia" ,
"Missouri" ,
"South Carolina" ,
"Tennessee" ,
"Vanderbilt" );
boolean isSorted = Ordering . natural (). isOrdered ( secConferenceEast );
assertTrue ( isSorted );
}
Strings sorted decending @Test
public void is_list_of_strings_sorted_decending_in_java_with_guava () {
List < String > secConferenceEastDecending = Lists . newArrayList (
"Vanderbilt" ,
"Tennessee" ,
"South Carolina" ,
"Missouri" ,
"Georgia" ,
"Florida" );
boolean isSorted = Ordering . natural (). reverse (). isOrdered ( secConferenceEastDecending );
assertTrue ( isSorted );
}
Strings sorted case insensitive @Test
public void is_list_of_strings_sorted_case_insensitive_in_java_with_guava () {
List < String > secConferenceEast = Lists . newArrayList (
"alabama" ,
"Alabama" ,
"ALABAMA" );
boolean isSorted = Ordering . from ( String . CASE_INSENSITIVE_ORDER ). isOrdered ( secConferenceEast );
assertTrue ( isSorted );
}
Is list sorted posted by Justin Musgrove on 18 March 2013
Tagged: java and java-collections
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All the code on this page is available on github:
IsListSorted.java